Question

Five mole of an ideal gas at 293 K are expanded isothermally from an initial pressure 0.4 kPa to a final
pressure of 0.1 kPa against a constant external pressure of 0.1 kPa. Calculate q, w, ,∆U and ∆H.
​

Answer 1

a. For an isothermal expansion against a constant pressure, we have:

`w =- P_(ex) (V_(2)-V_(1))`

`=- P_(ex) ((nRT)/(P_(2))-(nRT)/(P_(1)))=- P_(ex) ((1)/(P_(1))-(1)/(P_(2))) =- 9135J`

Since temperature is constant

`DeltaU = 0, DeltaH = 0,q =- W = 9135J`

b. For isothermal reversible expansion

`-w = 2.303nRT "log"(P_(1))/(P_(2))`

`= 2.303 xx5xx 8.324 xx 293 "log"(0.4)/(0.1)`

`rArr w =- 16888J`

`DeltaU = DeltaH = 0,q =- W = 16888J`

..

..

..

hope it helps and please mark as the brainliest answer.

Answer 2

Answer:

REFER TO THE ATTACHMENT