five moles of an ideal monatomic gas occupy a
Volume of 10m^3 temperature 300k it expands to
a volume 20m^3 adiabatically, then what is the Final
tempezature of
gas
?
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Answer:In an adiabatic process, PV
γ
=constant
or TV
γ−1
=constant
T
1
T
2
=(
V
2
V
1
)
γ−1
For monoatomic gas
γ=
3
5
T
2
=(300K)(
2V
V
)
3
5
−1
=189K
Change in internal energy
ΔU=nC
v
ΔT
=2(
2
3
)(
3
25
)(−111)
=−2.7kJ
Explanation:
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