Question

Five moles of an ideal monatomic has with an initial temperature of 127degree expand and in the process, absorbs 1200J of heat and do 2100J of work. What is the final temperature of gas? With full solution plzzzz

Answer 1

Answer:

Explanation:

Q=1200J  (Given)

W=-2100J (Given)

U=-900J (Given)

n = 5 moles  (Given)  

According to first law of thermodynamics - Q = ∆U+W

Where Q is heat added to system, ∆U is change in internal energy and W is work done on the gas.

= ∆U = n (no.of moles of gas) × R(universal gas constant) × ∆T(change in temperature)

Cv = 1.5R (monoatomic gas)  

T = 127°C  

Therefore, Tf -127 =-900/(5×12.465)  

= 189.3

Tf = 189.3° (final temperature of the gas)