Question

five moles of hydrogen is heated through 20K under constant pressure . If R=8.312 FIND THE EXTERNAL WORK DONE

Answer 1

The externa work is "831.4 J".

Explanation:

Work done under constant pressure,

W_isobaric = PΔV

We know that,

PΔV = nRΔT

⇒ W_isobaric = nRΔT

Given, ΔT = 20 K

⇒ W_isobaric = 5 ×8.314 × 20

⇒ W_isobaric = 831.4 J

Hence, The externa work is "831.4 J".

Answer 2

The work done is 831.2 J .

Given :

Number of moles , n = 5 moles .

Change in temperature , $\Delta T=20 K$ .

It is also given that the pressure is constant .

Therefore , work done , $W=P\Delta V$   ( For constant pressure )

We know , by real gas equation .

$P\Delta V=nR\Delta T$

Therefore , $W=nR\Delta T$

Putting all value in above equation :

We get ,

$W=5\times 8.312\times 20\\\\W=831.2\ J$

Hence , this is the required solution .

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Work , Power and Energy

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