Five numbers are arranged in increasing order.
The average of the first four numbers is 34 and
the average of the last four numbers is 40. Find the
difference of the last and the First number.??? pls fast ⚡⚡
Answers
Answered by
2
Answer:
24
Explanation:
(a+b+c+d)/4 = 34 so the sum a+b+c+d = 136 where a<b<c<d
(b+c+d+e)/4 = 40 so the sum b+c+d+e = 160 where b<c<d<e
b+c+d = 136-a
b+c+d = 160-e
thus 136-a = 160-e
and e= -(136-a-160) = a+24
therefore
the difference is 24
Answered by
0
24 answer
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