Question

) Five numbers are in continued proportion whose second term is 6 and fourth term is 54. Find

the numbers.​

Answer 1

I don't know any body else to give answer him back but I think 3 m

Answer 2

Answer:

-18, 6, 30 , 54, ...

Step-by-step explanation:

We know that the general formula is:

an = a1 + ( n - 1)d where a1 is the first term, n is the number of terms and d is the difference.

Given that 2nd term is 6:

a2 = a1 + (2 - 1)d = 6

a2 = a1 + d = 6

Given that 4th term is 54:

a4 = a1 + (4 - 1)d = 54

a4 = a1 + 3d = 54

Put the two equations together:

a1 + d = 6 ------------ [ 1 ]

a1 + 3d = 54 --------- [ 2 ]

Equation [ 2 ] - Equation [ 1 ]:

(a1 + 3d) - (a1 + d) = 54 - 6

a1 + 3d - a1 - d = 48

2d = 48

d = 24

Find the numbers:

Difference = 24

2nd Term = 6 (Given)

1st Term = 6 - 24 = -18

3rd Term = 6 + 24 = 30

4th term = 54 (Given)

Answer: The terms are -18, 6, 30 , 54, ...