Math, asked by gauri500, 1 year ago

five percent people in a town died due to some diseases and three percent of the remaining left the town if 276450 people are still in the town find the original number of people in the town

Answers

Answered by ImMohammedAnas
0
__HI__
five percent of the people died is equal to 276450/5 is 55 290

number of people left the town is 3 %
276450-55 290 is equal to 22 11

gauri500: thanks but.......
ImMohammedAnas: wait
ImMohammedAnas: the people who were killed in the disease is 13822. 50
ImMohammedAnas: the people who left the town is 8293. 50
ImMohammedAnas: the number of people left residing there is 2 54334
ImMohammedAnas: therefore 95 % of the people are still there
ImMohammedAnas: will you please mark Me brainliest
gauri500: sorry but still not getting the answer
Answered by TNMeghana
0

Answer:

Step-by-step explanation:

Let the total population of the village be X, and let the no. of people died be Y.

  • Than, Y =\frac{X*5}{100}          equ. (1)

Let the no. of people who left the town be Z,

  • Than, Z = \frac{(X-Y)*3}{100}
  • Z = \frac{(X - [X*5]/100]*3)}{100}      from equ. (1)
  • Z = \frac{[(100X - 5X)/100]*3}{100}
  • Z = \frac{95X * 3}{100*100}
  • Z = \frac{285X}{10000}     equ. (2)

So, X = Y + Z + 276450

  • X = \frac{5X}{100} + \frac{285X}{10000} + 276450   from equ.(2)
  • X - \frac{5X}{100} - \frac{285X}{10000} = 276450
  • \frac{10000X - 500X - 285X}{10000} = 276450
  • \frac{9217X}{10000} = 276450
  • X = \frac{276450*10000}{9217}
  • X = 299935

So, the original number of people in town was 299935.

Similar questions