Physics, asked by hellokriti1964, 1 year ago

Five point charges each of magnitude q placed at the five vertices of regular hexagon

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Answered by dhruv1375
0
Five point charges, each of the value +q coulombs are placed on the five vertices of a regular hexagon of side L metres. The magnitude of force on a charge -q coulomb placed at the centre of the hexagon is. Answer: If six samecharges are placed at six vertices then the attractive forces will cancel eachother.

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Answered by ITzRithik
0

Answer:

The attractive forces will cancell eachother.

so net attractive force= 0

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