Question

Five point charges, each of value + are placed on five vertices of a regular hexagon of side L. What is the magnitude of the force on a point charge of value -q placed at the centre of the hexagon? ​

Answer 1

Answer:

Among the five forces on five charges,2pairs(four) of forces are cancelled with each other since they are equal in magnitude and opposite in direction.

The resultant force is due to a single force given below.

F=

4πϵ

∘

1

×

l

2

q×q

F=

4πϵ

∘

1

×

l

2

q

2

(attractive in nature)