CBSE BOARD XII, asked by sharonbruce229, 10 months ago

Five point charges, each of value +q are placed on five vertices of a regular hexagon of side L. What is the magnitude of the force on a point charge of value
-q placed at the centre of the hexagon? (Entire procedure required) Plz help...

Answers

Answered by KANIAC05
2

Answer:

ZERO NEWTON

Explanation:

A charge placed at the center will be acted upon by five forces of equal magnitude due to the charges present at the vertices.

As all the forces are concurrent and of equal magnitude, they cancel out and thereby producing no net force. Hence the net force on the charge -q placed at the center is Zero.

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