Five resistances of resistance r are connected in the shape of letter a determine the total resistance
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from fig resistance in ABC
Rs=2r
in circuit AC
1/Rp=1/r+1/r
1/Rp=2/r
Rp=r/2
now in circuit FG
Rs=r+r+r/2
Rs=5r/2
hope it helps you
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The simplified diagram for resistance will be
So the total resistance of the circuit is
r=5+(3+7)×10(3+7)+10+5=15 Ω
The current through circuit is
I=1.515=0.1 A
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