Question

five resistors are connected as shown. find the ammeter reading when the circuit is closed​

Answer 1

Answer:

R=R1+R2(in series)

=3+3

=6 ohm

1/R=1/R1+1/R2(in parallel)

=1/6+1/3

=1+2/6

=3/6 =1/2

=1/R=1/2

R=2 ohm

R=R1+R2+R3(all over circuit)

=0.5+2+0.5

=3 ohm

V=IR

{v=potencial difference

I=current

R=resistance}

3=I*3

I=3/3

I=1 Ampere