Question

five resistors are connected in a circuit as shown in fig find tge ammeter reading when tge circuit is closed. ​

Answer 1

Answer:

R 6= r1+r2

= 3+3

=6 ohm

$\frac{1}{r} = \frac{1}{6} + \frac{1}{3}$

$\frac{1}{r } = \frac{1}{6 } + \frac{2}{6} = \frac{3}{6}$

$r = \frac{6}{3} = 2ohm$

• R effective = 0.5 ohm + 2 ohm +0.5 ohm
• R effective = 3 ohm

Ammeter Reading = I =v/r

=3/3

= 1 ampere

• Hope it helps you
• Please mark as branliest.

Answer 2

Answer:

2 A

Explanation:

First find the equivalent resistance .

starting from the top ,

consider part DCE , resistor DC and DE are in series so their equivalent resistance is 6 ohm .

now in place of those two resistors mentioned above consider one resistor of 6 ohm .

that resistor and the 3 ohm resistor are parallelly connected . cal. their equivalent resistance ( 1/6 + 1/3 ) and resiprocal of this will be the total resistance of the triangle above .

not the two 0.5 resistors and the equivalent resistance of above triangle are in series so add all the three you'll get the equivalent resistance .

now use V = IR

V= 3V

R = we havd calculated above ( 1.5 ohm )

find I ( current ) that will be the ammeter reading .

ammeter is a device which measures the current in the circuit .

thank you.