Question

Five resistors are wired in series. Their values are 10 Ω, 56 Ω, 82 Ω, 120 Ω and 180 Ω.a) If these resistors are connected to a 6 V battery, what is the current flowing out of the battery? *​

Answer 1

Since the resistors are connected in series, so the equivalent resistance of all the resistors is the sum of their individual resistances.

∴ Equivalent resistance = R = (10+56+82+120+180) Ω = 448 Ω

Potential difference = V = 6 V

By Ohm's law,

V = IR

or, I = V/R

or, Current = I = 6/448 A = 0.134 A (approximately)

Hope it helps!

Answer 2

Given :-

• Five resistors are connected in series. 10 Ω , 56 Ω , 82 Ω , 120 Ω and 180 Ω.
• these resistors are connected to a 6 V battery; so, potential difference, V = 6 V

To find :-

• Current flowing out of the battery, I = ?

Knowledge required :-

• When 'n' number of resistors are connected in Series then the equivalent resistance is calculated as

    R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ ..... Rₙ

• [ohm's Law] Relation between Resistance (R) , potential difference (V) and current (I) through the circuit

    R = V / I

Calculation :-

Calculating equivalent resistance of given 5 resistors

→ R = 10 + 56 + 82 + 120 + 180

→ R = 448 Ω

Calculating current (I) through the circuit

→ R = V / I

→ I = V / R

→ I = 6 / 448

→ I = 0.0134 A

therefore,

• Current through the circuit is 0.0134 Amperes.