Five resistors each of 3 ohm are connected as shown in figure calculate the resistance between the points :
1. A and B
2. Between the point C and D
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between the point c and d
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1=> Resistances AE and EB are in series ,
so their net resistance AEB=3+3=6ohm
Now AEB & AB are parellel
So net resistance R bw point A & B
1/R=1/AEB+1/AB=1/6+1/3=1/6+2/6=3/6
=1/2
R=ohm
2=>CA,R&BD are in series so their net resistance=3+2+3=8ohm
Hope it is easy for u
so their net resistance AEB=3+3=6ohm
Now AEB & AB are parellel
So net resistance R bw point A & B
1/R=1/AEB+1/AB=1/6+1/3=1/6+2/6=3/6
=1/2
R=ohm
2=>CA,R&BD are in series so their net resistance=3+2+3=8ohm
Hope it is easy for u
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