Question

five resistors of 2ohm 4ohm 6ohm 3 ohm and 7ohm are connected in a square ABCD in which the fifth resistor is connected as a diagonal BD of the square ABCD find the equivalent resistance between the points A and C

Answer 1

AB and AD connected in series then
RS = 2+4 = 6ohm

CB and CD connected in series then
RS = 6+3 = 9ohm

then , 6ohm , 9ohm and 7ohm resistors are connected in parallel
Rp = R1×R2×R3/R1+R2+R3
Rp = 6×9×7/6+9+7
Rp = 378/22
Rp = 17.18 ohm

so equivalent resistance is 17.18 ohm

Answer 2

ANSWER
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R1 = 2 ohm
R2  =3 ohm
R3 = 4 ohm
R4 = 6 ohm

This is a Wheatstone Bridge coz 
R1/R2 = R3/R4

So, The diagonally connected wire can be neglected

Hence R1 and R2 are in series 
Req = 2 + 3 = 5 ohm

Similarily, R3 and R4 are in series 
Req = 4 + 6 = 10 ohm


THESE TWO Req ARE IN PARALLEL COMBINATION

1/Req = 1/10 + 1/5
1/Req = 3/10

Req = 10/3

Req = 3.33 ohm
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