Five resistors of resistance ‘R’ are connected such that they form a letter ‘A’. Find the
effective resistance across the free ends.
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And is 8R/3 ohm. ... solution is in the pic :)
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Answer:
the effective resistance across the free ends = 8R/3
Explanation:
Top two resistances will be in series with each other
hence R + R = 2R
& these two resistance would be in parallel with Resistance in Middle
Hence Resistance = 1/(1/2R + 1/R)
= 2R/(1 + 2)
= 2R/3
Now this resistance would be in series with another two left resistances
so Total Resistance = R + 2R/3 + R
= (3R + 2R + 3R)/3
= 8R/3
the effective resistance across the free ends = 8R/3
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