Question

Five resistors R1 = R5 = 6 Ω, R2 = R4 = 3 Ω and R3 = 12 Ω are connected with a 12 V battery as shown. Then​

Answer 1

The equivalent resistance of the  5Ω, 10Ω, 30Ω resistors connected in parallel is

Rp1=51+101+301

=306+3+1=3010

∴Rp=3Ω

∴, the total resistance of the given circuit is 3 Ohms.

The total current can be calculated using the Ohm's law as the value of voltage (V) is already given.

using Ohm's law

Voltage=Current×Resistance

⇒I=RV=312=4A

Current through each resistor can be calculated by applying Ohm's law given that the voltage of the circuit and the individual resistances of each resistor is already given.

Current through 5Ω resistor =RV=512=2.4A

Current through 10Ω resistor 

Answer 2

Answer:

The current flowing is 2.4 A

Explanation:

5 ohm, 10 ohm, and 30 ohm resistors linked in parallel have an equivalent resistance of

Rp1=51+101+301

=306+3+1=3010

∴Rp=3Ω

The circuit in question has a total resistance of 3 Ohms.

Ohm's law can be used to determine the total current since the voltage (V) value is already known.

employing Ohm's law

Voltage=Current×Resistance

⇒I=RV=312=4A

Given that the circuit's voltage and each resistor's individual resistance are known, the current flowing through each resistor may be estimated using Ohm's law.

5 resistor current = RV=512 = 2.4 A

flowing across a 10 ohm resistor

The relationship between electric current and potential difference is stated by Ohm's law. Most conductors' current is directly inversely proportional to the voltage applied to them. German physicist Georg Simon Ohm was the first to experimentally confirm Ohm's law. Resistance, abbreviated R in the equation, is the proportionality constant that has ohms as its unit of measure.

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