Chemistry, asked by adityamalhotra71, 6 months ago

Five solutions a b c d and e are tested in universal indicator showed pH as 4, 1,11, 7 and 9 respectively which solution is option:a) neutral b) strongly alkaline c) strongly acidic d) weakly acidic e) weakly alkaline arrange the ph in increasing order of hydrogen ion concentration

Answers

Answered by jasonfrancis1811420
13

Answer:

a) D is neutral, as its pH value is equal to 7  

b) C is strongly alkaline, as its pH value is 11.  

c) B is strongly acidic, as its pH value is equal to 1  

d) A is weakly acidic, as its pH value is equal to 4 and more than solution B.  

e) E is weakly alkaline, as its pH value is equal to 9 and less than C.  

pH value of the given solution in increasing order of hydrogen-ion concentration: 11<9<7<4<1

Answered by prag3188
1

Explanation:

D . solution - pH - 7

C . solution - pH - 11

B . solution - pH - 1

A . solution - pH. - 4

C . solution - pH -. 9

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