five solutions a b c d and e when tested with universal indicator shows ph as 4 1 11 7 and 9 respectively which solution
Answers
Answered by
5
Answer:
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Explanation:
pH↑[H
+
]
conc.
↓
[H
+
]
conc.
↑ Acid Strength↑
B→ Strongly Acidic
A→ Weakly Acidic
D→ Neutral [pH=7]
E→ Weakly Alkaline
C→ Strongly Alkaline
So, [H
+
]
conc.
is B>A>D>E>C
Answered by
7
Answer:
Explanation:
a) D is neutral, as its pH value is equal to 7
b) C is strongly alkaline, as its pH value is 11.
c) B is strongly acidic, as its pH value is equal to 1
d) A is weakly acidic, as its pH value is equal to 4 and more than solution B.
e) E is weakly alkaline, as its pH value is equal to 9 and less than C.
pH value of the given solution in increasing order of hydrogen-ion concentration: 11<9<7<4<1
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