Science, asked by nithishkumark94, 8 months ago

five solutions a b c d and e when tested with universal indicator shows ph as 4 1 11 7 and 9 respectively which solution​

Answers

Answered by cynt041064
5

Answer:

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Explanation:

pH↑[H  

+

]  

conc.

​  

[H  

+

]  

conc.

​  

↑ Acid Strength↑

B→ Strongly Acidic

A→ Weakly Acidic

D→ Neutral [pH=7]

E→ Weakly Alkaline

C→ Strongly Alkaline

So, [H  

+

]  

conc.

​  

 is B>A>D>E>C

Answered by monalibagade10
7

Answer:

Explanation:

a) D is neutral, as its pH value is equal to 7

b) C is strongly alkaline, as its pH value is 11.

c) B is strongly acidic, as its pH value is equal to 1

d) A is weakly acidic, as its pH value is equal to 4 and more than solution B.

e) E is weakly alkaline, as its pH value is equal to 9 and less than C.

pH value of the given solution in increasing order of hydrogen-ion concentration: 11<9<7<4<1

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