Question

five solutions a b c d and e when tested with universal indicator showed ph as 5,2,14 ,7 and 8 respectively which solution is a) neutral b) strongly alkaline c)strongly acidic d)weakly acidic e)weakly alkaline​

Answer 1

Answer:

Solution

pH↑[H

+

]

conc.

↓

[H

+

]

conc.

↑ Acid Strength↑

B→ Strongly Acidic

A→ Weakly Acidic

D→ Neutral [pH=7]

E→ Weakly Alkaline

C→ Strongly Alkaline

So, [H

+

]

conc.

is B>A>D>E>C

Answer 2

Answer:

a) neutral: solution d with the pH 7

b) strongly alkaline: solution c with the pH 14

c) strongly acidic: solution b with the pH 2

d) weakly acidic: solution a with the pH 5

e)weakly alkaline: solution e with the pH

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thanks!!