five solutions a b c d and e when tested with universal indicator showed ph as 5,2,14 ,7 and 8 respectively which solution is a) neutral b) strongly alkaline c)strongly acidic d)weakly acidic e)weakly alkaline
Answers
Answered by
2
Answer:
Solution
pH↑[H
+
]
conc.
↓
[H
+
]
conc.
↑ Acid Strength↑
B→ Strongly Acidic
A→ Weakly Acidic
D→ Neutral [pH=7]
E→ Weakly Alkaline
C→ Strongly Alkaline
So, [H
+
]
conc.
is B>A>D>E>C
Answered by
3
Answer:
a) neutral: solution d with the pH 7
b) strongly alkaline: solution c with the pH 14
c) strongly acidic: solution b with the pH 2
d) weakly acidic: solution a with the pH 5
e)weakly alkaline: solution e with the pH
(you can also refer the attachment to know more)
thanks!!
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