Five students A,B,C,D, E are competing in a long distance race . Each students probability of winning the race is given below A=20%, B=22%, C=7%, E=36% who is likely to win the race
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Answer:
E would win the race ....
Answered by
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Answer:
=39/50
Step-by-step explanation:
It is given that
Probabilities of five students A, B, C, D and E is
P(A)=20%,P(B)=22%,P(C)=7%,P(D)=15%,P(E)=36%
(i)Student E is most likely to win the race as P(E)=36%
(ii) Student C is likely to win the race as P(C)=7%
(iii) Sum of probabilities =P(A)+P(B)+P(C)+P(D)+P(E)
Substituting the values
=20%+22%+7%+15%+36%
=100%
(iv) Here the favorable outcomes that either A or D will win =20%+15%=35%
So the P (either A or D will win) =35/100=7/20
(v)(a) Favorable outcomes that B will win =22%
So P(S)=22/100=11/50
(b) S
′
=B will not win the race
(c) P(S
′
)=1−P(S)
Substituting the values
=1−11/50
=(50−11)/50
=39/50
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