Chemistry, asked by devikapk2003, 4 months ago

Five successive ionisation enthalpies of a metal are 577.6, 1816.7, 2744.8, 11578.0 and 14831.0 KJ
mot respectively. The stable oxidation state of the metal would be
1) +2
2) +4
3) +5
4) +3​

Answers

Answered by vrunda1410
3

Answer:

1) +2

due to after 1816.7 to 2744.8 IE gap will more that means it jump from outer orbital to inner

Answered by nanthitha18
1

ANSWER: +3

EXPLANATION:

1). 1st and 2nd

1816.7-577.6 = 1239.1

2). 2nd and 3rd

2744.8-1816.7 = 928.1

3). 3rd and 4th

11578-2744.8 = 8833.2

4). 4th and 5th

14831.0-11578.0 = 2353.0

here,8833.2 is very large so at step 3 it is large

it has 3 valence electron

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