Five successive ionisation enthalpies of a metal are 577.6, 1816.7, 2744.8, 11578.0 and 14831.0 KJ
mot respectively. The stable oxidation state of the metal would be
1) +2
2) +4
3) +5
4) +3
Answers
Answered by
3
Answer:
1) +2
due to after 1816.7 to 2744.8 IE gap will more that means it jump from outer orbital to inner
Answered by
1
ANSWER: +3
EXPLANATION:
1). 1st and 2nd
1816.7-577.6 = 1239.1
2). 2nd and 3rd
2744.8-1816.7 = 928.1
3). 3rd and 4th
11578-2744.8 = 8833.2
4). 4th and 5th
14831.0-11578.0 = 2353.0
here,8833.2 is very large so at step 3 it is large
it has 3 valence electron
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