Question

Five terms are inserted between 2 and 32 such that the terms form an arithmetic progression.
Find the fourth term of this progression.
a. 17
b. 18
c. 19
d. 20​

Answer 1

Answer:

Let the five terms be a,b,c,d,e

Arithmetic progression -

2,a,b,c,d,e,32

As all are in arithmetic progression

So, for last term we have a formula

$\sf{l} =\sf{a+(n-1)d}$

Hence,

$\sf{32} =\sf{2+(7-1)d}$

$\sf{32} =\sf{2+6d}$

$\sf{30} =\sf{6d}$

$\sf{5} =\sf{d}$

$\sf{d} =\sf{5}$

As d = 5

So,lets see the arithmetic progression -

2,7,12,17,22,27,32

Your fourth term is 17

Option A is correct