Question

Five times the 5th term of an AP is equal to
ten times the 10 th term. If the common
difference of the AP is 7, then find its 25th
term.​

Answer 1

Answer: d = 7 (Given)

5th term = a5 = a+4d = a+28

10th term = a10 = a+9d = a+63

ATQ,

5(a5) = 10(a10)

5(a+28) = 10(a+63)

a+28 = 10(a+63) /5

a+28 = 2(a+63)

a+28 = 2a+126

0 = a+126-28

0 = a+98

-98 = a

25th term = a25 = a+24d

a25 = (-98) + 24*7

a25 = (-98) + 168

a25 = 70

Hope it helps!

Plz. mark it as the brainliest.