Question

Five times the age of Sita is 10 yrs more than four times the age of Gita. Find their ages if their sum of the ages is 11 years​

Answer 1

Let present age of Sita be x and Gita be y.

x+y=11 ---------1.

5x=10+4y ------2.

​5x-4y = 10  

Multiply first equation by 5 and subtract from equation2  

9y = 45  

y = 5  

so x = 11-5 = 6 years  

So present age of Sita is 6 year and Gita be 5 year

Answer 2

Given:-

• Five times the age of Sita is 10 years more than four times the age of Gita.
• The sum of their age is 11 years.

To Find:-

• Present ages of Gita and Sita.

Assumption:-

• Let the age of Sita be x
• And age of Gita be y

Solution:-

As it is given that sum of ages of Sita and Gita is 11 years.

Hence,

x + y = 11

=> x = 11 - y ----------------> (i)

Now,

Also its given that five times the age of Sita is 10 more than 4 times the age of Gita.

Hence,

5x = 4y + 10 ---------------> (ii)

Substituting the value of x from equation (i) into equation (ii)

= 5x = 4y + 10

=> 5(11 - y) = 4y + 10

=> 55 - 5y = 4y + 10

=> -4y - 5y = -55 + 10

=> -9y = -45

=> y = -45/-9

=> y = 5

Putting the value of y in equation (i)

= x = 11 - y

=> x = 11 - 5

=> x = 6

Therefore,

• Age of Sita = x = 6 years
• Age of Gita = y = 5 years

________________________________

Verification!

Let us see whether five times the age of Sita is 10 years more than 4 times the age of Gita or not.

5 times the age of Sita = 5 × 6 = 30 years

4 times the age of Gita = 4 × 5 = 20 years

Difference between the age of Gita and Sita:-

= 30 - 20 = 10 years.

Hence, yes five times the age of Sita is 10 more than the age of Gita.

Hence Verified!

________________________________