five times the complement of an angle is 10 degree more than its supplement what is the measure of the angle also find its supplement
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13
Let the angle = x
complement of x = 90-x
supplement of x = 180-x
five times the complement of x is 10 degree more than its supplement
=> 5(90-x) = 10 + (180-x)
=> 450 - 5x = 10 + 180 - x
=> -5x + x = 10 + 180 - 450
=> -4x = -260
=> 4x =260
=> x = 260/4 = 65°
Thus the angle is 65°
Supplement = 180 - 65 = 115°
complement of x = 90-x
supplement of x = 180-x
five times the complement of x is 10 degree more than its supplement
=> 5(90-x) = 10 + (180-x)
=> 450 - 5x = 10 + 180 - x
=> -5x + x = 10 + 180 - 450
=> -4x = -260
=> 4x =260
=> x = 260/4 = 65°
Thus the angle is 65°
Supplement = 180 - 65 = 115°
Answered by
4
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☬ YOUR ANSWER ☬
╘═════════════════════╛
Let the angle = x
complement of x = 90-x
supplement of x = 180-x
As stated⤵⤵⤵
⭕five times the complement of x is 10 degree more than its supplement
⏩5(90-x) = 10 + (180-x)
⏩450 - 5x = 10 + 180 - x
⏩ -5x + x = 10 + 180 - 450
⏩-4x = -260
⏩4x =260
⏩ x = 260/4 = 65°
•°• the angle is 65°
Supplement = 180 - 65 = 115°
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
☬ YOUR ANSWER ☬
╘═════════════════════╛
Let the angle = x
complement of x = 90-x
supplement of x = 180-x
As stated⤵⤵⤵
⭕five times the complement of x is 10 degree more than its supplement
⏩5(90-x) = 10 + (180-x)
⏩450 - 5x = 10 + 180 - x
⏩ -5x + x = 10 + 180 - 450
⏩-4x = -260
⏩4x =260
⏩ x = 260/4 = 65°
•°• the angle is 65°
Supplement = 180 - 65 = 115°
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
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