Question

five times the sum of the digits of a two digit number is 9 less than the number formed by reversing its digits . if four times the value of the digit at ones place is equal to half of the place value of the digit at tens place find the number​

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Linear Equations in Two Variable

Solution of Linear Equations in Two Variables

The sum of the digits of tw...

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Asked on December 26, 2019 byFalak Dugar

The sum of the digits of two digit number is 5. The number obtain by reversing the order of digits diminished the original number by 9. Find the number.

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ANSWER

Let the tens digit =x

Let the units digit =y

The sum of digits of a two digit number is 5, so x+y=5

When the digits are reversed, the number is 9 more than the original 

since x is your tens digits, its value is 10x.

So, yo have the value of your original number 10x+y.

Now, reverse the digits the number =10y+x

So, equation formed =10y+x=(10x+y)=9

⇒10y−y=10x−x+9

⇒9y=9x+9

⇒9y−9x=9

⇒9(y−x)=9

⇒y−x=9/9=1

y−x=1

y+x=5

_________

2y=6

⇒y=6/2

⇒y=3

Put y in y−x=1

3−x=1

−x=1−3

x=2

∴ The original number is 10x+y=10(2)+