Question

five year age, father age was 7 times the age of his son 5 years later the father age will be 3 times the age of his son find their present age​

Answer 1

Step-by-step explanation:

5 years ago,

Let the age of the son be x years

father's age = 7x years

After 5 years, that is the present year

son's age = x+5 years

father's age = 7x+5 years

7x+5 = 3(x+5)

7x+5 = 3x+15

7x-3x = 15+5

4x = 20

x = 20/4

= 5

Son's age = 10 years

Father's age = 40 years

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Answer 2

Answer:

Five years hence, a man's age will be three times the age of his son. Five years ago, the man was seven times as old as his son. And His son's be y years. Hence, man's present age = 40 years and son's present age = 10 years.

Step-by-step explanation:

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