Math, asked by AdarshMishra931, 11 months ago

five year ago a man thrice year old as his son and 10 year leter he will become twice as his son find their present age with solution​

Answers

Answered by asahilthakur
2

Step-by-step explanation:

Let the age of son 5 years ago be x.

Age of man = 3x

Ten years later,

Age of son = x + 10

Age of man = 3x + 10

According to Question,

3x + 10 = 2 (x + 10)

3x + 10 = 2x + 20

3x - 2x = 20 - 10

x = 10

Hence, 5 years ago son was 10 years and man was 30 years old.

Therefore, son's present age = 15 years

Man's present age = 25 years

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