five year ago a man was 7 times old as his son..five years hence..he will be 3 times as old as his son...find their present age
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Answered by
7
Let the present ages of the man be x and son be y.
Acc. to question,
Five years ago:
(x-5) = 7(y-5) .........(i)
Five years hence:
(x+5) = 3(y+5) ........(ii)
∴ (i) ⇒ x-5 = 7y-35
⇒x-7y = -35+5
⇒ x-7y = -30 ........(iii)
and (ii) ⇒ x+5 = 3y+15
⇒ x-3y = 15-5
⇒ x-3y = 10........(iv)
Now by solving eq. iii and iv we get,
y = 10, x = 40.
Therefore, present age of man is 40 years and son is 10 years.
Hope it helps. Please mark as brainliest! Thank you. :)
Acc. to question,
Five years ago:
(x-5) = 7(y-5) .........(i)
Five years hence:
(x+5) = 3(y+5) ........(ii)
∴ (i) ⇒ x-5 = 7y-35
⇒x-7y = -35+5
⇒ x-7y = -30 ........(iii)
and (ii) ⇒ x+5 = 3y+15
⇒ x-3y = 15-5
⇒ x-3y = 10........(iv)
Now by solving eq. iii and iv we get,
y = 10, x = 40.
Therefore, present age of man is 40 years and son is 10 years.
Hope it helps. Please mark as brainliest! Thank you. :)
jasveer700:
thenkew
please mark as brainliest :)
Answered by
2
Let the present ages of the man be x and son be y.
Acc. to question,
Five years ago:
(x-5) = 7(y-5) .........(i)
Five years hence:
(x+5) = 3(y+5) ........(ii)
∴ (i) ⇒ x-5 = 7y-35
⇒x-7y = -35+5
⇒ x-7y = -30 ........(iii)
and (ii) ⇒ x+5 = 3y+15
⇒ x-3y = 15-5
⇒ x-3y = 10........(iv)
Now by solving eq. iii and iv we get,
y = 10, x = 40.
Therefore, present age of man is 40 years and son is 10 years.
Acc. to question,
Five years ago:
(x-5) = 7(y-5) .........(i)
Five years hence:
(x+5) = 3(y+5) ........(ii)
∴ (i) ⇒ x-5 = 7y-35
⇒x-7y = -35+5
⇒ x-7y = -30 ........(iii)
and (ii) ⇒ x+5 = 3y+15
⇒ x-3y = 15-5
⇒ x-3y = 10........(iv)
Now by solving eq. iii and iv we get,
y = 10, x = 40.
Therefore, present age of man is 40 years and son is 10 years.
you copycat ~_~
you copied exactly what i wrote sentence by sentence
not a single change
grow up dude. learn to answer yourself
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