Question

five year ago a mother was seven times as old as her daughter. five years hence she will be three as old as her daughter. find their present ages​

Answer 1

Step-by-step explanation:

Let the present age of the daughter be 'x'.

5 years ago,

Daughter's age = x - 5

Mother's age = 7(x - 5) = 7x - 35

♦ At present,

Daughter's age = x - 5 + 5 = x

Mother's age = 7x - 35 + 5 = 7x - 30

♦ 5 years hence,

Daughter's age = x + 5

Mother's age = 7x - 30 + 5 = 7x - 25

♦ But according to the question, after 5 years, mother will be thrice daughter's age.

→→→ 7x - 25 = 3(x + 5)

=> 7x - 25 = 3x + 15

=> 7x - 3x = 15 + 25

=> 4x = 40

=> x = 40/4

=> x = 10

•°• Daughter's present age = x = 10 years.

•°• Mother's present age = 7x - 30 = 7(10) - 30 = 70 - 30 = 40 years.

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