Question

five year ago Sunny was three times as old as Mini. 10 year later Sunny would be twice as old as Mini. how old are they now.​

Answer 1

Answer:

sunny 's age is 20 and mini 's age is 10

Step-by-step explanation:

let sunny age be x

let mini age be y

x=2y

x-5=3(y-5)

2y-5=3y-15

y=10

x=2y=20

Answer 2

Given:-

• Five years ago, sunny was three times as old as Mini.
• 10 years later,Sunny would be twice as old as Mini.

To find:-

• Find the present ages ?

Solutions:-

• Let the present age of Sunny be 'x' years and that of Mini be 'y' years

Five years ago, sunny was three times as old as mini.

Sunny's age = (x – 5) years

Mini's age = (y – 5) years

=> (x - 5) = 3(y - 5)

=> x - 5 = 3y - 15

=> x = 3y - 15 + 5

=> x = 3y - 10 ........(i).

10 years later,Sunny would be twice as old as Mini.

Sunny's age = (x + 10) years

Mini's age = (y + 10) years

=> (x + 10) = 2(y + 10)

=> x + 10 = 2y + 20

=> x = 2y + 20 - 10

=> x = 2y + 10 ..........(ii).

Putting the value of 'x' from equation (ii) in equation (i).

=> (2y + 10) - 3y = -10

=> 2y + 10 - 3y = -10

=> 2y - 3y = -10 - 10

=> -y = - 20

=> y = 20

Putting the value of 'y' in equation (ii).

=> x = 2y + 10

=> x = 2 × 20 + 10

=> x = 40 + 10

=> x = 50

So,

• Sunny's age = x = 50 years
• Mini's age = y = 20 years

Hence, the Sunny's age = x = 50 years is present ages and Minu's age = y = 20 years is present ages.