Question

Five year ago the age of Maya was seven times the age of her son. the age of Maya will be three times the age of her son in 5 years. represent the situation as an equation and draw its graph. find the present age of mother and son.

Answer 1

Answer
Age of maya=40 years
Age of her son =10 years

Answer 2

Answer and explanation:

Let the present age of Maya be x and that of her son be y.

Five years ago,

Maya's age = (x - 5) years

Her son's age = (y - 5) years

According to the question, we have

(x - 5) = 7(y - 5)

x - 5 = 7y - 35

x = 7y - 35 + 5

x = 7y - 30                  ------------------------- (i)

In 5 years,

Maya's age = (x+5) years

Her son's age = (y+5) years

Accordingly, we have

x + 5 = 3(y + 5)

x + 5 = 3y + 15

x = 3y + 15 - 5

x = 3y + 10                   ----------------------------- (ii)

Subtracting (ii) from (i), we get

x - x = (7y - 30) - (3y + 10)

0 = 7y - 30 - 3y - 10

0 = 4y - 40

4y = 40

y = 40/4

y = 10 years

Putting the value of y in (i), we get

x = 3(10) + 10

x = 30 + 10

x = 40 years

Hence, Maya's age = x = 40 years

Her son's age = y = 10 years

The graph of equations (i) and (ii) is given below

And from the graph, we get the solution as x = 40 and y = 10. (Same as the calculated values).

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