Math, asked by GauravNarang7243, 1 year ago

Five year hence the age of jacob will be three times that of his son .five years ago jacob age was seven times that of his son. what are their prents ages

Answers

Answered by Steph0303
14
Hey mate !!

Here's the answer !!

Refer to the attachment !!

Hope this helps !!

Cheers !!
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Answered by Anonymous
8

Let x be the present age of Jacobs son and y be the present age of Jacob. 5 year hence it has relation :


(y + 5) = 3(x + 5)


y + 5 = 3x + 15


3x - y + 10 = 0 ............... (Eqn 1)


5 years ago it has relation :-


(y - 5) = 7(x - 5)


7x - y - 30 = 0 ............ (Eqn 2)


From Equation 1


Y = 3x + 10 .......... (Eqn 3)


On substituting the value of y in Eqn. 2 we get :-


7x – (3x + 10) – 30 = 0


4x – 40 = 0


x = 10


On substituting x = 10 in eqn 3


y = 3 × 10 + 10


y = 40


Hence the present age of Jacob = 40 years and son age = 10 years


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