Question

five years ago a father was 7 times as old as his son 5 years hence the father will be three times as old as his son find their present ages

Answer 1

Answer:

Step-by-step explanation:

age of father

(x-5) = 7(y-5)

x-5=7y -35

7y - x = 30-------------(2)

after 5 years

(x + 5) = 3(y+5)

x+5 = 3y +15

x-3y =10------------(1)

now solve

7y - x= 30

-3y + x =10

4y=20

y=5

sub y=5 in(1)

x-45=10

x=55

the age of father is 55 years

and the age of son is 5 years