Question

Five years ago a man's age was 5 times the age of his son three years hence twice his age will be equal to 6 times his son's age find their present age

Answer 1

Answer:

man's present age = 45 years

son's present age  = 13 years

Step-by-step explanation:

let the man's present age be x and son's age be y.

five years ago,

x - 5 = 5(y-5)

    x  =  5(y-5) + 5

   x   = 5y - 25 + 5

   x   =  5y - 20

three years hence,

2(x+3)            = 6(y+3)

2x + 6            =  6y + 18

2(5y-20) + 6  =  6y + 18

10y - 40 + 6   =  6y + 18

    10y - 6y     =   18 + 40 - 6

              4y    =   58 - 6

              4y    =   52

                y    =   13