Question

Five years ago,a man's age was thrice his son's age.Fifteen years hence his age will be twice his son's age,his present age (in years)?​

Answer 1

Step-by-step explanation:

Let the age of a man = x years And the age of his son = y years 

Ten years hence,

Man's age =(x+10) years

Son's age =(y+10) years

According to the question, (+10=2(+10)

⇒x+1=2+20

⇒x=2y+20−10

⇒x=2y+10…(i)

Ten years ago, 

Father's age =(x−10) years 

Son's age =(y−10) years 

According to the question, (x−10)=4(y−10)

⇒x−10=4y−40

⇒x=4y−30…(ii)

From Eq. (i) and (ii), we get 2y+10=4y−30

⇒2y−4y=−30−10

⇒−2y=−40

⇒y=20

On putting the value of y=20 in Eq. (i), we get x=2y+10

⇒x=2(20)+10

⇒x=50

Hence the age of the man is 50 yrs and the age of his son

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