Question

Five years ago, a man was 7 times as old as his daughter, while five years hence, the man will be 3 times as old as his daughter. Find their present ages

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

let father age= x

daughter's age =y

5 Years hence, father age= x+5

daughter's age = y+5

So, (X+5) = 3(Y+5)

= x= 3y+10

5 yrs ago, father's age =x-5

daughter's age =y-5

So, (x-5) = 7(y-5)

3y+10-5 = 7y - 35

4y = 40

y = 10 (daughter's age)

Daughter's age is 10 year

father's age is 40 year.