Question

Five years ago a man was 7 times as old as his son.5 years hence he will be 3 times as old as his son.find their present ages

Answer 1

Let The Age Of The Man Be x.

Now Age Of Son Be y.

According To 1st Condition

x-5 = 7(y-5)

x-5 = 7y-35

x+30 = 7y

x = 7y-30

According To Second Condition

x+5 = 3(y+5)

x+5 = 3y+15

Now Substitute Value Of x as 7y-30

7y-30+5 = 3y+15

7y-25 = 3y+15

4y = 40

y = 10

Now Age Of Father = x = 7y-30 = 7*10-30 = 40

So Age Of Father = 40 And AGe Of Son = 10