five years ago a man was 7 times as old as his son. five years hence, the father will be three time as old as his son. find their present age?
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Answer:
Age of the son =x
Age of the father=7x
Present ages=x+5 and 7x+5
future age of the son=x+10
father=7x+10
7x+10=3(x+10)
x=5
7x=35
x+5=5+5=10
son age =10
father age =7x+5=7*5+5=40
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Answered by
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Step-by-step explanation:
Man = 7x + 5
Find their age 5 years later:
Son = x + 5 + 5 = x + 10
Man = 7x + 5 + 5 = 7x + 10
Solve x:
The Man is 3 times as old as his son
7x + 10 = 3(x + 10)
7x + 10 = 3x + 30
4x = 20
x = 5
Find their present age:
Son = x + 5 = 5 + 5 = 10 years old
Man = 7x + 5 = 7(5) + 5 = 40 years old
Answer: The man is 40 and the son is 10 years old.
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