Question

Five years ago , a man was 7 times as old as his son . five years hence , the father will be 3 times as old as his son . find their present ages

Answer 1

Answer:

Let the age of son five years ago be x years The age of man five years ago be 7x years After five years, son’s age is x + 5 years After five years father’s age is 7x + 5 years So, since five years, the relation in their ages are 7x + 5 + 5 = 3(x + 5 + 5) 7x + 10 = 3x + 15 + 15 7x + 10 = 3x + 30 7x – 3x = 30 – 10 4x = 20 x = 5 ∴ Present father’s age is 7x + 5 = 7(5) + 5 = 35 + 5 = 40years Present son’s age is x + 5 = 5 + 5 = 10

Step-by-step explanation:

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