Question

five years ago, A man was 7 times as old as his son Wildfire hence, the man will be four times as old as his son. find their present age.​

Answer 1

Let the man's age be x yrs and his son's age be y yrs.

5 years ago

Father's age= x-5

Son's age = y-5

According to the question

x-5=7(y-5)

x-5=7y-35

x-7y=-30 (1)

Five Years later

Father's age= x+5

Son's age =y+5

According to the question

x+5=4(y+5)

x-4y=15 (2)

x-7y=-30

x-4y=15

- 3y=-45

y=45/3=15

x-7y=-30

x-7(15)=-30

x=-30+105

x=75

Father's age (x)=75yrs

Wildfire's age(y)=15yrs