Question

Five years ago a man was 7 times as old his son . After 5 years he will be thrice as old his son . Find their present ages

Answer 1

Answer:

Let son's age be = x

Then Father's age = 7x

After 5 years

Son's age = x + 5

Father's age = 7x + 5

A.T.P

7x + 5 = 3(x + 5)

7x + 5 = 3x + 15

7x - 3x = 15 -5

4x = 10

x = 10/4

x = 2.5

Son's age = x = 2.5 years

Father's age = 7x = 2.5 *7 = 17.5 years