Question

five years ago A man was 7 times as old his son five years hence the man will be three times as old as his son find the present age ​

Answer 1

Answer:

father's age = 40 years

son's age = 10 years

Step-by-step explanation:

let the present age of father be x

and the present age of son be y

5 years ago father's age = x - 5

5 years ago son's age = y - 5

it's given that father is 7 times the age of son

x - 5 = 7(y - 5)

x - 5 = 7y - 35

x - 7y = - 35 + 5

x - 7y = - 30 equ (1)

5 years later father will be 3 times the age of son

x + 5 = 3(y + 5)

x + 5 = 3y + 15

x - 3y = 15 - 5

x - 3y = 10 equ (2)

subtract equ (1) - (2)

x - 7y = -30

x - 3y = 10

we get

4y = 40

y = 40/4

y = 10

substitute y = 20 in equ (1)

x - 7y = - 30

x - 7(10) = - 30

x - 70 = - 30

x = - 30 + 70

x = 40

therefore the age of father = x = 40 years

age of son = y = 10 years

hope you get your answer