Question

five years ago a man was
eight times as old as his son,
five years hence the father
will be thrice the age of her
son find their present age ​

Answer 1

Answer:

5 year ago

age of son=x

man=8x

now

son=x+8

man=8x+8

5 year later

son =x+8+5=x+13

man=8x+8+5=8x+13

$8x + 13 = 3(x + 13) \\ 8x + 13 = 3x + 39 \\ 8x = 3x + 26 \\ 8x - 3x = 26 \\ 5x = 26 \\ x = \frac{26}{5} \\ x = 5.2$

son =5.2+8=13years 2 months

man 41.6+8=49years 6 months

Step-by-step explanation:

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