Question

five years ago a man was seven times as old as his son five year hence the father will be 3 times as old as his son find their present ages​

Answer 1

Answer:

Step-by-step explanation:

Let the man current age X and his son current age Y.

Now according to question

5 Years ago

X-5 =7 (Y-5) eq (1)

And 5 Years later

X+5=3 (Y+5) eq (2)

Solving both eq 1 qnd 2

X-5=7Y-35 and X+5=3Y+15

X=7Y-30 and X=3Y+10

Now equating both X

7Y-30=3Y+10

7Y-3Y=10+30

4Y=40

So Y=10 and X=3Y+10= 40