Question

Five years ago a man was seven times as old as his son Five years hence, the father will be three times as old as his son. Find there present ages.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Age of the son =x

Age of the father=7x

Present ages=x+5 and 7x+5

future age of the son=x+10

father=7x+10

7x+10=3(x+10)

x=5

7x=35

x+5=5+5=10

son age = 10yrs.

father age =7x+5=7*5+5=40yrs.