Question

five years ago , a man was seven times as old as his son . five years hence , he will be three times as old as his son . find their present age​

Answer 1

Answer:

age of son = 10 and age of father 40

Step-by-step explanation:

let the son's age be x in five year ago,

then, according to question

$7x + 10 = 3(x + 10)$

$7x + 10 = 3x + 30 \\ 7x - 3x = 30 - 10 \\ 4x = 20 \\ x = 5$

Therefore son's age was 5 in five year ago then their present age will be 5+5=10

then the age of father will be 35+5 = 40