Question

five years ago , a man was seven times as old as his son . five years hence ,father will be three times as old as his son . find their present age.


explain me this question.
needn't want answer ....
just explanation ​

Answer 1

Answer:

10 years, 40 years

Step-by-step explanation:

5 years ago :

Age of Son = x

Age of father = 7x

Present ages :

Age of son = x + 5

Age of father = 7x + 5

5 years hence :

Age of son = x + 10

Age of father = 7x + 10

Now,

Father will be three times as old as his son.

7x + 10 = 3(x + 10)

=> 7x + 10 = 3x + 30

=> 4x = 20

=> x = 5

Therefore,

Present age of Son = 10 years

Present age of father = 40 years

Hope it helps!

Answer 2

Answer:

here is ur answer hopefully it helps you follow me...